Question 930129
A)


t = (xbar - mu)/(s/sqrt(n))
t = (9.9 - 9.2)/(2/sqrt(61))
t = 2.733587


The test statistic is approximately t = 2.733587


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B)


Use a calculator or table to get 


P(t > 2.733587) = 0.0041


Note: the degrees of freedom is df = n-1 = 61-1 = 60


So the p-value is 0.0041


Notice how the p-value (0.0041) is smaller than the significance level (alpha = 0.01), so we reject the null hypothesis H0. We reject H0 whenever (pvalue) < (alpha).


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