Question 930056
2x^2 -3=-5x  Set to Zero
2x^2 + 5x - 3 = 0  Factor
<font size=3 color="red">F</font>	First terms  2x^2
<font size=3 color="red">O</font>	Outside terms + <font size=3 color="red">I</font>	Inside terms = 5x
<font size=3 color="red">L</font>	Last terms   -3

(2x -1)(x +3)= 0   
(2x -1) = 0 Set each factor to Zero  and solve
x = 1/2 
0r 
(x +3)= 0
x = -3
..........
using the quadratic formula
2x^2 -3=-5x  Set to Zero.. Format: ax^2 + bx + c = 0
2x^2 + 5x - 3 = 0   
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-5 +- sqrt( 25+24 ))/(4) }}}
{{{x = (-5 +- sqrt( 49 ))/(4) }}}
{{{x = (-5 +- 7)/(4) }}}
x = 12/4 = -3  0r a = 2/4 = 1/2