Question 78646
Solving by substitution, you want to find what x or y equals from one of those equations, then plug what you find into the other equation, as follows:

We can use the bottom line to find x:

-x + 3y = -1
get -x on one side

-x = -3y - 1
multiply all by -1

x = 3y + 1

Use this in the other equation.

4(3y + 1) - 12y = 5
12y + 4 - 12y = 5
4 = 5

Hmm...I am not finding this equation to be solvable.

Using an alternate method, multiply the bottom equation by 4, so the x part cancels out, then add the 2 equations.

4x - 4x -12y + 12y = 5 - 4
0 = -1

The answer I am finding is "empty set"
I am sorry if I am either wrong or if my explanation is unclear.  If it is unclear though just worry about understanding the first part I said.