Question 929902
the vertex form of a Parabola opening up(a>0) or down(a<0), 
{{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry , 
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
..........
parabola with a vertex of (-3,-2) and a point of (6,-3)
y = a(x+3)^2 - 2
-3= a(9)^2  -2
-1/81 = a
y = (1/81)(x+3)^2 - 2

{{{drawing(300,300,   -20,20,-20,20,  blue(line(-3,20,-3,-20))  ,  
 grid(1),
circle(-3,-2,0.4),
graph( 300, 300, -20,20,-20,20,0,  (1/81)(x+3)^2 - 2))}}}