Question 929860
{{{8/root(7,x^15)}}} = 8/x^(15/7) = 8x^(-15/7)
.......
{{{a^0 = 1}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{(a^p)^q = a^(p*q)}}}
{{{(xy)^n = x^n*y^n}}}
{{{root(a,p)*root(a,q) = root(a,p*q)}}}
{{{root  (n, (x/y)) = root(n,x)/root(n,y)}}}
x^(1/n) = {{{root(n,x)}}}   
{{{root(n,x^m))}}} = x^(m/n) *****