Question 929786
Using the second equation in the first,
{{{2x+3(-x)=-3}}}
{{{2x-3x=-3}}}
{{{-x=-3}}}
{{{x=3}}}
Then,
{{{y=-3}}}
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{{{2x+3y=-3}}}
{{{3y=-2x-3}}}
{{{y=-(2/3)x-1}}}
{{{graph(300,300,-5,5,-5,5,-(2/3)x-1)}}}
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{{{y=-x}}}
{{{drawing(300,300,-5,5,-5,5,circle(3,-3,0.2),graph(300,300,-5,5,-5,5,-(2/3)x-1,-x))}}}