Question 929840
1.Edwin is twice as old as Ruel. In three years, Edwin will be 13 less 
than twice as old as Ruel. Find their present ages.
Equations:
E = 2R
E+3 = 2(R+3)-13
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Substitute for "E" and solve for "R"::
2R + 3 = 2R +6 - 13
2R + 3 = 2R - 7
That is a contradiction.
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 2. Olan is 3 years older than his sister Mary. One-third of Olan's age 
is two years less than one-half his sister's ageone years ago.
 Find their present ages.
Equations:
O = M + 3
(1/3)O = (1/2)(M-1)-2
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(1/3)(M+3) = (1/2)M - (3/2)
Multiply thru by 6 to get:
2M+6 = 3M + 9
M = -3
That is a contradiction.
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Cheers,
Stan H.