Question 929757
If you want to get this equation into standard form {{{ax^2+bx+c=0}}}, then...



{{{-3(x+1)^2 +2=-5}}}



{{{-3(x+1)^2 +2+5 = 0}}}



{{{-3(x+1)^2 +7 = 0}}}



{{{-3((x+1)(x+1)) +7 = 0}}}



{{{-3(x^2+2x+1) +7 = 0}}}



{{{-3x^2-6x-3 +7 = 0}}}



{{{-3x^2-6x+4 = 0}}}



The equation is now in standard form {{{ax^2+bx+c=0}}} where {{{a = -3}}}, {{{b = -6}}} and {{{c = 4}}}
------------------------------------------------------------------------------------------------------------------------


If you need more one-on-one help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=I%20Need%20Algebra%20Help">jim_thompson5910@hotmail.com</a>. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).


Alternatively, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.


Jim

------------------------------------------------------------------------------------------------------------------------