Question 929698
you know that {{{sqrt(-1)=i}}}-complex root
{{{(sqrt(-1))^2=-1}}}

or {{{i*i=i^2=sqrt(-1)*sqrt(-1)=(sqrt(-1))^2=-1}}}

it's not clear why you have {{{i22}}}; you might mean this {{{(sqrt(i^2))^2=(sqrt(-1))^2=-1}}}