Question 929582
If a & b are the two legs of the triangle, then {{{a^2 + b^2 = (sqrt(18))^2}}} which turns into {{{a^2 + b^2 = 18}}}


Solve for b to get {{{b = sqrt(18 - a^2)}}}


There are infinitely many ordered pairs (a,b) that make that equation true. If you sketch the graph of {{{y = sqrt(18 - x^2)}}} and make sure that {{{0<x<sqrt(18)}}}, then you'll see all of the possible combos of (a,b). Each combo is a point on the curve of the graph.