Question 929569


the sides of a triangle measure {{{4}}},{{{ 8}}} and {{{10}}}. 

if the smallest side of a {{{similar}}} triangle measures {{{12}}},then we use proportion to find the remaining sides of this triangle

let the remaining sides of this triangle be {{{b}}} and {{{c}}}

{{{4:8}}} is equal to {{{12:b}}}

so, we have {{{4:8=12:b}}}........solve for {{{b}}}

{{{4b=12*8}}}

{{{b=(12*cross(8)2)/cross(4)}}}

{{{b=12*2}}}

{{{b=24}}}

and

{{{8:10=24:c}}}

{{{8c=24*10}}}

{{{c=240/8}}}

{{{c=30}}}