Question 929272
(Tan^2)/secx))= secx-cosx
I seen in a video of a teacher transforming tan^2x into (sec^2x-1)/secx)) but how is that possible 1+tan^2x=sec^2x? How did the 1 go negative? How do you solve it with tanx=sinx/cosx as well? Sorry im asking for too much.
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{{{tan^2(x)=(sin^2(x)/cos^2(x))}}}
{{{tan^2(x)=((1-cos^2(x))/cos^2(x))=((1/cos^2(x))-1)=sec^2(x)-1)}}}
or 
1+tan^2(x)=sec^2(x)