Question 929346
There are {{{52}}} cards to start. 

Four of these {{{52}}} cards are kings. 

Therefore the probability of drawing a {{{king}}} on the first drawing {{{P(K1)}}}is {{{4/52}}} or {{{1/13}}}.

After drawing {{{one}}} king there are only {{{51}}} cards remaining, of which {{{three}}} are kings. The probability of drawing a {{{king}}} on the second drawing {{{P(K2)}}} is {{{3/51}}}.

The probability of drawing {{{two}}} kings {{{in}}} a {{{row}}} is therefore the {{{product}}} of both draws or

{{{P(K1)*P(K2)}}}

= {{{(4/52) * (3/51)}}}

= {{{12/2652}}}

which reduces to

= {{{1/221 }}}

so, your answer is b) {{{1/221 }}}