Question 929298
{{{log (6, w+3) + log (6, w - 2) = 2 }}} 
{{{log(6,(w+3)(w-2))}}}= 2
(w+3)(w-2) = 36
w^2 + w -6 = 36
w^2 + w - 42 = 0
(w+7)(w-6)= 0  (w = -7 an extraneous root...results in undefined logarithm)
w = 6