Question 929298
{{{log (6, (w+3)) + log (6, (w-2)) = 2}}}
{{{log (6, (w+3)(w-2)) = 2}}}
{{{(w+3)(w-2) =36}}}
{{{w^2+w-6=36}}}
{{{w^2+w-42=0}}}
{{{(w-6)(w+7)=0}}}
Two solutions:
{{{w-6=0}}}
{{{w=6}}}
and
{{{w+7=0}}}
{{{w=-7}}}
However since this leads to negative arguments for the log functions, this is not a valid solution.
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{{{w=6}}}