Question 923179

How do I solve 3y+3x=3 and 2y+6x=2 by substitution?
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3y + 3x = 3_____3(y + x) = 3(1)_____y + x = 1______y = 1 - x ------- eq (i)
2y + 6x = 2_____2(y + 3x) = 2(1)______y + 3x = 1 ------ eq (ii)
1 - x + 3x = 1 ------- Substituting 1 - x for y in eq (ii)
- x + 3x = 1 - 1
2x = 0
x = {{{0/2}}}, or {{{highlight_green(x = 0)}}}

y = 1 - 0 ------- Substituting 0 for x in eq (i)
{{{highlight_green(y = 1)}}}