Question 929142
The age of the father is four times that
 of his daughter and the age of the son is half of
 that of his mother. The wife is 8 years younger to
 her husband and the brother is seven years older
 than his sister. What is the age of the mother?
-----
Equations:
f = 4d
s = (1/2)m
f = m + 8
s = d + 7
---------------------
Solve for "m"::::
---------------------
m = 2s
m = f -8
--------
2s = f-8 = 4d-8 = 4(s-7)-8
-----
So, 2s = 4s-28-8
2s = 4s - 36
2s = 36
s = 18 (son's age)
---
Since s = (1/2)m, mom's age = 36
-------------------------------------
Cheers,
Stan H.
----------------