Question 929033
{{{ (sin (pi/4) cos (pi/6) - sin (pi/6) cos (pi/4))^2 }}}
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rearrange terms:
{{{(sin(pi/4)cos(pi/6)-cos(pi/4))sin(pi/6)^2}}}
Identity: sin(x-y)=sinxcosy-cosxsiny)
{{{sin(pi/4)cos(pi/6)-cos(pi/4)sin(pi/6)=sin(pi/4-pi/6)=sin(3pi/12-2pi/12)=sin(pi/12)}}}
(sin (pi/4)cos(pi/6)-sin(pi/6)cos(pi/4))^2=sin^2(π/12)