Question 927984
If {{{a=n}}} then, {{{b=n+2}}}
So,
{{{b^2-a^2=(n+2)^2-n^2}}}
{{{b^2-a^2=(n^2+4n+4)-n^2}}}
{{{b^2-a^2=4n+4}}}
{{{b^2-a^2=4(n+1)}}}
{{{b^2-a^2=4b}}}