Question 927996
1.{{{A+B=76}}}
2.{{{B-4A=16}}}
.
.
.
{{{B=16+4A}}}
Substitute into eq. 1,
{{{A+16+4A=76}}}
{{{5A+16=76}}}
{{{5A=60}}}
{{{A=12}}}
Then,
{{{12+B=76}}}
{{{B=64}}}