Question 928142
1.{{{3x^2-y^2=3}}}
2.{{{2x-y=1}}}
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From eq. 2,
{{{y=2x-1}}}
{{{y^2=(2x-1)^2}}}
{{{y^2=4x^2-4x+1}}}
Substituting into eq. 1,
{{{3x^2-(4x^2-4x+1)=3}}}
{{{-x^2+4x-1=3}}}
{{{-x^2+4x-4}}}
{{{x^2-4x+4=0}}}
{{{(x-2)^2=0}}}
{{{x-2=0}}}
{{{x=2}}}
Then,
{{{y=2(2)-1}}}
{{{y=3}}}