Question 928795

I don't know how to solve this! System of equations by the elimination method: 
x/2 + y/8 = 3
x - y/4 = 0
<pre>
{{{x/2 + y/8 = 3}}}______4x + y = 24 ------ Multiplying by LCD, 8 ------ eq (i)
{{{x - y/4 = 0}}}______4x - y = 0 ------- Multiplying by LCD, 4 ------ eq (ii)
8x = 24 ------- Adding eqs (ii) & (i)
x = {{{24/8}}}, or {{{highlight_green(x = 3)}}}

4(3) - y = 0 ------- Substituting 3 for x in eq (ii)
  12 - y = 0
     - y = - 12
       y = {{{(- 12)/(- 1)}}}, or {{{highlight_green(y = 12)}}}