Question 78633
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 75 women are randomly selected, find the probability that they have a mean height between 63 and 65 inches.
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Find the z-score of 63 and of 65:
z(63)=(63-63.6)/[2.5/sqrt(75)]=-2.07846...
z(65)=(65-63.6)/[2.5/sqrt(75)]=4.8497...
P(-2.07846<=z<=4.8497)=0.9812
Cheers,
Stan H.