Question 928750
{{{2x-5y=4}}}.......eq.1....both sides multiply by {{{3}}}

{{{3x-2y=4}}}.......eq.2....both sides multiply by {{{-2}}}
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{{{6x-15y=12}}}.......eq.1
{{{-6x+4y=-8}}}.......eq.2
____________________..............add

{{{6x-15y+(-6x+4y)=12+(-8)}}}

{{{cross(6x)-15y-cross(6x)+4y=12-8}}}

{{{-11y=4}}}

{{{y=4/-11}}}

{{{y=-4/11}}}

now find {{{x}}}

{{{2x-5y=4}}}.......eq.1

{{{2x-5(-4/11)=4}}}

{{{2x+20/11=4}}}

{{{2x=4-20/11}}}

{{{2x=44/11-20/11}}}

{{{2x=24/11}}}

{{{x=(cross(24)12/11)/cross(2)}}}

{{{x=12/11}}}

so, intersection point is: ({{{12/11}}},{{{-4/11}}}) or as decimal ({{{1.1}}},{{{-0.4}}})


{{{drawing( 600, 600, -10, 10, -10, 10,circle(1.1,-0.4,.12),locate(1.1,-0.4,p(1.1,-0.4)), graph( 600, 600, -10, 10, -10, 10, 2x/5-4/5,3x/2-2)) }}}