Question 928749
{{{(-4a^3b^1)^2  = 16a^6b^2}}}
.......
{{{a^0 = 1}}}

{{{( x^m )( x^n ) = x^( m + n )}}} ****
{{{x^m/x^n=x^(m-n)}}}
{{{(a^p)^q = a^(p*q)}}} ****