Question 928738
{{{25-(x+2)^2 = 5^2-(x+2)^2}}}


{{{5^2-(x+2)^2}}} is in the form {{{a^2 - b^2}}} where {{{a = 5}}} and {{{b = x+2}}}


use the formula {{{a^2 - b^2 = (a-b)(a+b)}}} to get...



{{{a^2 - b^2 = (a-b)(a+b)}}}


{{{5^2-(x+2)^2 = (5-(x+2))(5+(x+2))}}} Plug in {{{a = 5}}} and {{{b = x+2}}}


{{{5^2-(x+2)^2 = (5-x-2)(5+x+2)}}}


{{{5^2-(x+2)^2 = (3-x)(7+x)}}}


{{{25-(x+2)^2 = (3-x)(7+x)}}}



Therefore, {{{25-(x+2)^2}}} factors to {{{(3-x)(7+x)}}} which is equivalent to {{{-(x-3)(7+x)}}} (I factored a negative out of {{{3-x}}} to get {{{-(x-3)}}})


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