Question 78552
Yes, you have set up the problem correctly. However, your Step 2
is more properly written as:
{{{f(g(x))=-x(-x^2-2x+1)+1}}} rather than f= ...
Now, you can just plug -3 in there for x and solve it.

Alternatively, you could find g(-3) first as below, then 
plug that result into the f(x) equation:

First, calculate {{{g(-3)}}}:
{{{g(-3)=-(-3)^2-2*(-3)+1}}}
{{{g(-3)=-9+6+1=-2}}}

Now, plug this in to the f(x) equation. The "x" is now the 
value you found for g(-3):

{{{f(g(-3))=1-(-2)}}}
{{{f(g(-3))=3}}}