Question 78593
{{{log5 (16)-log5 (2t)=log5 (2)}}}

Recognize that the left side can be re-written according to an algebraic
property of logarithms:

{{{log5 (16/2t)=log5 (2)}}}

This now allows you to rewrite the equation with each side being the 
exponent of 5 without changing the value of the equation:

{{{5^(log5 (16/2t))=5^(log5 (2))}}}

This form now allows you to use one of the inverse properties
of logarithms to re-write the equation as follows:

{{{16/2t=2}}}

Then just solve for t:
{{{16=4t}}}
{{{t=4}}}