Question 928633

passes through the origin:({{{0}}},{{{0}}}

{{{ 3x-6y=12}}} ...find a slope first

{{{ 3x-12=6y}}}

{{{ 3x/6-12/6=y}}}

{{{ y=highlight((1/2))x-2}}} => slope is {{{1/2}}}

parallel lines have same slope, so the equation of the line parallel to given line will be:

{{{y=mx+b}}}....from given point we know that {{{b=0}}} (the line passes through the origin)

{{{y=mx+b}}} => slope is {{{1/2}}}

{{{y=(1/2)x}}} ....the equation of the line parallel to given line 


{{{ graph( 600, 600, -10, 10, -10, 10, (1/2)x, (1/2)x-2) }}}