Question 928309
We have *[tex \large \frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}]. The sum of the roots of the quadratic *[tex \large ax^2 + bx + c] is *[tex \large -\frac{b}{a}] and their product is *[tex \large \frac{c}{a}], so *[tex \large \alpha + \beta = -\frac{b}{a}] and *[tex \large \alpha \beta = \frac{c}{a}]. Hence the answer is *[tex \large \frac{-\frac{b}{a}}{\frac{c}{a}} = -\frac{b}{c}].