Question 928243
Solve the equation sin(theta)+cos(theta)= 2(sin(theta)- cos(theta)), for 0<theta<360
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sinx+cosx=2sinx-cosx
2cosx-sinx=0
2cosx=sinx
2cosx=&#8730;(1-cos^2(x))
4cos^2(x)=1-cos^2(x)
5cos^2(x)-1=0
cos^2(x)=1/5
cosx=±&#8730;(1/5)
x&#8776;63.43&#730;, -116.57&#730;,-243.43&#730;, 296.57&#730;