Question 928139
a= 0.05 test the claim that u>16 using P value n= 50 x=16.3 o= 1.2 find p value. 
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z(16.3) = (16.3-16)/1.2 = 0.3/1.2 = 0.25
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p-value = P(z > 0.25) = normalcdf(0.25,100) = 0.40
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Note: You may have meant that x-bar = 16.3 in which case
z(16.3) = (16.3-16)/(1.2/sqrt(50)) = 1.77
Then p-value = P(z > 1.77) = normalcdf(1.77,100) = 0.038
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Cheers,
Stan H.
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