<PRE><B>Question 928108</B>
Let 68-x = Larger Number
      x  = Smaller Number

The sum of two no. is 68.

68-x + x = 68

When the larger no. is divided by the smaller one, we get 2 as quotient and 5 as remainder.

(68-x)/x = (2)+(5/x)

(68-x)/x = (2x/x)+(5/x)

Multiply both side by x

68-x = 2x+5
  63 = 3x
  21 = x

Substitute x for 21

68 - 21 = 47

The Larger number is 47 while the smaller number is 21.

Check

47 + 21 = 68

47/21 = 2 remainder 5




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