Question 928018

Two bicyclists leave a rest stop going in the same direction. Bicyclist A travels at 20 mph and bicyclist B travels at 15 mph. B leaves 3 hours before A. After how many miles will A catch up to B?
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Let distance A travels to catch B, be D
Then: {{{D/20 = D/15 - 3}}}
3D = 4D - 180 ----- Multiplying by LCD, 60
3D – 4D = - 180 
- D = - 180
D, or distance A travels to catch up to B = {{{(- 180)/(- 1)}}}, or {{{highlight_green(180)}}} miles