Question 78588
LET X=THE EQUAL SIDES.
THEN THE BASE=X-4.
THE PERIMETER IS THE SUM OF ALL THREE SIDES.
THUS WE HAVE THE FOLLOWING EQUATION FOR THE PERIMETER
X+X+(X-4)=32
3X-4=32
3X=32+4
3X=36 
X=36/3
X=12 FOR THE EQUAL SIDES.
THUS THE BASE=12-4=8
PROOF
32=12+12+8
32=32