Question 78595
{{{2x^2 + 3x + 4 = 0}}}
divide both sides by 2
{{{x^2 + (3/2)x + 2 = 0}}}
subtract 2 from both sides
{{{x^2 + (3/2)x = -2}}}
divide the coefficient of x by 2, square it, and add it to both sides
{{{x^2 + (3/2)x + 9/16= -2 + 9/16}}}
{{{(x + (3/4))^2 = -23/16}}}
If you take the square root of both sides,
the solution for x is imaginary