Question 927896
Simon has $85.
Joe has $70.
Joe spends more than $5 than Simon, but we do not know how much they spent, so we will express it as "x".
At the end, Simon has twice as much money as left as Joe, so we will know the solution will be S = 2J, assuming that S = Simon and J = Joe.
Based on the statement above, we can assume that.
{{{ S = 85 - x }}}
{{{ J = 70 - (x + 5) }}}
As with the equation above, we can plug in S and J with the equation of S = 2J
{{{ 85 - x = 2(70 - (x + 5)) }}}
{{{ 85 - x = 2(70 - x - 5) }}} Distribution
{{{ 85 - x = 140 - 2x - 10) }}} Distribution
{{{ 85 - x = 130 - 2x }}} Combine Like Terms
{{{ 85 - 85 - x = 130 - 85 - 2x }}} Subtraction Property of Equality
{{{ -x + 2x = 45 - 2x + 2x }}} Addition Property of Equality
{{{ x = 45 }}} Simplify

Now we will plug in x for the S and J.
{{{ S = 85 - x }}}
{{{ S = 85 - 45 }}} Substitution
{{{ S = 40 }}} Simplify

{{{J = 70 - (x + 5) }}} 
{{{ J = 70 - (45 + 5) }}} Substitution
{{{ J = 70 - 50 }}} Combine Like Terms
{{{ J = 20 }}} Simplify
Now, we will plug in S and J for the S = 2J equation to verify if it is true.
{{{ S = 2J }}}
{{{ 40 = 2(20) }}} Substitution
{{{ 40 = 40 }}}

Simon has $40 and Joe has $20.