Question 926467
How many different three-digit even numbers can be formed from the set of integers from 1 to 9 inclusive if no repetitions are allowed.

If we could  allow 0 to come first there would be 

5 ways to choose the third digit. {0,2,4,6,8}
9 ways to choose the first digit.
8 ways to choose the second digit.

That's 5*9*8 = 360 ways

From that we must eliminate all those beginning with 0,
such as 098.

We can coose the last digit any of 4 ways {2,4,6,8}
We can choose the second digit any of 8 ways (not 0 nor
the digit chosen for the third digit.)

That's 4*8 or 32 to eliminate from the 360.

Answer: 360-32 = 328

Edwin</pre>