Question 927328
Let  x be the amount invested @ 10 % per year
 Let y be the amount invested @  8 % per year
 x+y= $ 5900.......................eq(1)
interest on amount x  = 10 % of X
                     ={{{ (10/100)8x}}}
                     {{0.1x}}}
Interest on amount y = 8 % of y
                      = {{{ (8/100)*y}}}
                      ={{{0.08y}}}
Total interest for whole amount  = $ 534
hence 
         0.1x x+0.08 y =534.............eq(2)
*[invoke linear_substitution "x", "y", 1, 1, 5900, 0.1, 0.08, 534 ]
Result":  x= $ 3100
          y=$2800