Question 927295
log9(x+8)-log9(x+3)=log9x
{{{log(9,((x+8)/(x+3)))=log(9,(x))}}}
(x+8)/(x+3)=x
x^2+3x=x+8
x^2+2x-8=0
(x+4)(x-2)=0
x=-4 (reject, x>0)
or
x=2