Question 927500
Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given conditions.
sec &#952; = &#8722; 3/2; 180° < &#952; < 270°
sin(&#952;/2) =
cos(&#952;/2) =
tan(&#952;/2) = 
***
{{{secx=-3/2}}}
{{{cosx=-2/3}}}180° < &#952; < 270°
{{{sin(x/2)=sqrt((1-cosx)/2)=sqrt(1+(2/3)/2)=sqrt(5/6)}}}
{{{cos(x/2)=-sqrt((1+cosx)/2)=-sqrt(1-(2/3)/2)=-sqrt(1/6)}}}
{{{tan(x/2)=sin(x/2)/cos(x/2)=-sqrt(5)}}}