Question 927356
a) n = (zSD/ME)^2 = (1.96*35/19)^2 = 13.0359  0r 14
b) n = (zSD/ME)^2 = (2.0537*35/19)^2 = 14.312 0r 15
c) n > 14, n = (zSD/ME)^2 = (1.96*35/18)^2 = 14.5246  0r 15
d) Sample size part b is Larger  due to  increased confidence Level.
e) ME = 1.645(12) = 57.575  (round as directed)