Question 10629
I expect that you meant to write...(^2 is square) rather than...(^2 is square root).  This would make more sense so I'll proceed on that basis. Rewrite the equation into standard form.

{{{2x^2 - 2x + 3 = 0}}} Use the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}

{{{x = (-(-2)+-sqrt((-2)^2-4*2*3))/(2*2)}}}

{{{x = (2+-sqrt(4-24))/4}}}  

{{{x = (2/4)+-sqrt(-20)/4}}}

{{{x = (1/2) +- sqrt(-4*5)/4}}}

{{{x = (1/2) +- (2/4)sqrt(-5)}}}

{{{x = (1/2) +- (1/2)sqrt(5)i}}} 

{{{x = (1/2)(1+sqrt(5)i)}}} or {{{x = (1/2)(1 - sqrt(5)i)}}}