<PRE><B>Question 927307</B>
r = w/t
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x = rate of slow pipe
y = rate of fast pipe
y = 3x
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1/(x + y) = 6
1 = 6(x + y)
1 = 6x + 6y
1 = 6x + 6*3x
1 = 6x + 18x
1 = 24x
x = 1/24
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y = 3x
y = 3/24
y = 1/8
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r = w/t
t = w/r
t = w/y
t = 1/(1/8)
t = 8
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answer:
How long it takes the faster pipe working alone to empty a full tank = 8 hours
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