<PRE><B>Question 927307</B>
One pipe can empty a tank 3 times faster than another pipe.
slower pipe:: time = 3x hrs ; rate = 1/(3x) job/hr
faster pipe:: time = x hrs ; rate = 1/x job/hr
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Starting with a full tank,if both pipes are turned on,it takes 6 hrs.to empty the ta/hrnk.
Together:: time = 6 hrs/job ; rate = 1/6 job
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how long does it take the faster pipe working alone to empty a full tank?
Equation::
rate + rate = together rate
1/x + 1/(3x) = 1/6
6 + 2 = x
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x = 8 hrs (time for the faster pipe to do the job)
3x = 24 hrs (time for the slower pipe to do the job)
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Cheers,
Stan H.
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