Question 927251
p(def) = .05, p(good) = .95 , n = 20
Accept if x ≤ 2
P(x ≤ 2) = binomcdf(20, .05, 2) = .9245 0r 92.45%
..........
p(def) = .15 , n = 20
reject if x > 2
P(x > 2) = 1 - P(x ≤ 2) = 1 - binomcdf(20, .15, 2) = 1 - .4049 = .5951 0r 59.51%
......
 Using a TI calculator 0r similarly a Casio fx-115 ES plus