Question 926315
{{{(matrix(2,2,0.2,0.9,0.8,0.1))*(matrix(2,1,x,y))=(matrix(2,1,x,y))}}}
{{{(matrix(2,2,-0.8,0.9,0.8,-0.9))*(matrix(2,1,x,y))=(matrix(2,1,0,0))}}}
which leads to,
{{{-0.8x+0.9y=0}}}
{{{0.8x=0.9y}}}
So if {{{x=0.9*lambda}}},{{{y=0.8*lambda}}}
So then,
{{{(matrix(2,1,x,y))=lambda*(matrix(2,1,0.9,0.8))}}}
and the steady state vector would be,
{{{V[ss]=(matrix(2,1,0.9,0.8))}}}