Question 927190
{{{e^(i*theta)=cos(theta)+i*sin(theta)}}}
{{{theta=(5/6)pi}}}
{{{cos((5/6)pi)=-sqrt(3)/2}}}
{{{sin((5/6)pi)=1/2}}}
So then,
{{{e^(i*((5/6)pi))=-sqrt(3)/2+(1/2)i}}}