Question 927113

let numbers be {{{x}}} and {{{y}}}

{{{3y=7x+3}}}....eq.1

{{{5x+1=2y}}}....eq.2
___________________________

{{{5x+1=2y}}}....eq.2...solve for {{{y}}}

{{{(5/2)x+1/2=y}}}....substitute in eq.1

{{{3((5/2)x+1/2)=7x+3}}}....eq.1.solve for {{{x}}}

{{{(15/2)x+3/2=7x+3}}}

{{{7.5x=7x+3-1.5}}}

{{{7.5x-7x=1.5}}}

{{{0.5x=1.5}}}....both sides multiply by {{{10}}} to get whole numbers

{{{5x=15}}}

{{{x=15/5}}}

{{{highlight(x=3)}}}

now, find {{{y}}}


{{{y=(5/2)x+1/2}}}...plug in {{{3}}} for {{{x}}}

{{{y=(5/2)3+1/2}}}

{{{y=(15/2)+1/2}}}

{{{y=7.5+0.5}}}

{{{highlight(y=8)}}}