Question 926962
sin θ = 1/2  {{{sqrt(2^2 - 1^2) = sqrt(3)}}}
cos θ = - √3/2
csc θ = 1/(1/2) = 2
sec θ = 1/(-√3/2) = -2/√3 =  -2√3/ 3
tan θ = sinθ/cos θ = {{{(1/2)/(-sqrt(3)/2 )= -sqrt(3)/3}}}